ether_
Account Details
SteamID64 76561198064711665
SteamID3 [U:1:104445937]
SteamID32 STEAM_0:1:52222968
Country United States
Signed Up November 10, 2014
Last Posted March 15, 2025 at 3:49 PM
Posts 758 (0.2 per day)
Game Settings
In-game Sensitivity
Windows Sensitivity
Raw Input  
DPI
 
Resolution
 
Refresh Rate
 
Hardware Peripherals
Mouse  
Keyboard  
Mousepad  
Headphones  
Monitor  
1 ⋅⋅ 37 38 39 40 41 42 43 ⋅⋅ 51
#9 lfp Nameless team in Recruitment (looking for players)

good group of dudes who want to improve at the game

posted about 7 years ago
#28 S25 LFP Scout in Recruitment (looking for players)
pastebin 3:35 PM - mastrej: tbh, I want to do my friend fyg a favor
3:35 PM - mastrej: she's done so much for me
3:35 PM - mastrej: and she gets upset a lot when she carries and her team still can't capitalize
3:35 PM - mastrej: Consider this my little present to her
3:35 PM - mastrej: getting rid of dead weight
3:35 PM - mastrej: like u

what the fuck

posted about 7 years ago
#17 The TF2 Riddle in Off Topic

if it didn't specify that they had to be positive integers, you don't get integers nearly as large: (11,9,-5) and (11,4,-1) are two examples

getting the answers are still difficult but it's cool how just by specifying that the ans has to be positive you get much bigger numbers

posted about 7 years ago
#577 what's yo inches/360 in Off Topic

800 dpi
1.8 in game
11.4 in/360

I play any class

posted about 7 years ago
#13 Chicago LAN? in LAN Discussion

If it happens before school starts I'd definitely go, lots of friends that I want to meet

posted about 7 years ago
#12 jamie lft in Recruitment (looking for team)

seen her around for a while, has good aim and nice from my experiences. very underrated pickup

posted about 7 years ago
#4 math help (arithmetics) in Off Topic
Bob_Marleyidk if I misunderstand your notation, but 0 mod any number is 0. So
X^2 + 1 = 0 mod(p) = 0
x^2 = -1
so, x = +i, -i. Which aren't in Z.

0 mod p=/=0. any number that has a remainder of 0 when divided by p is equal to 0 mod p.
so if p=7 then 0, 7, 14, etc are all 0 mod p

posted about 7 years ago
#2 math help (arithmetics) in Off Topic

suppose there is such a solution x in Z
since p = 3 (mod 4), let p = 4k + 3 for some k in Z
x^2 + 1 = 0 (mod p) => x^2 = -1 (mod p) => x^4 = 1 (mod p)
then x^(p-1) = x^(4k+2)= x^4k * x^2 = (x^4)^k * x^2 = 1 * -1 = -1 (mod p)
but Fermat’s Little Theorem states x^(p-1) = 1 (mod p), so we have a contradiction.
thus there are no solutions x in Z

posted about 7 years ago
#2 b4nny watches porn on stream !! in The Dumpster

why

posted about 7 years ago
#5183 Frag Clips Thread in Videos

https://www.youtube.com/watch?v=VKGL9frrRhI

been recording and editing nonstop since grand finals

posted about 7 years ago
#2 moy lft in Recruitment (looking for team)

insane at demo, deserves a shot at playing invite again

posted about 7 years ago
#32 Tino LFT in Recruitment (looking for team)

Tino can definitely play the classes he listed at the levels listed. He's a nice person who was very easy to work with on medic. Pick him up :)

posted about 7 years ago
#6 speedy lft in Recruitment (looking for team)

We picked him up after our roamer left in the pre season and he turned out to be the underrated pickup of the season. Despite having only open exp he has very good dm and he was very easy to work with. If our team doesn't stick together please pick him up, he deserves a great team and can definitely play invite.

Show Content
cursed to get 2nd place
posted about 7 years ago
#1 ether lft in Recruitment (looking for team)

edit: my team is alive no longer lft

demo invite
soldier IM/invite (if ur desperate)
scout IM
med for friendly people (pref high IM+)

past few seasons i felt like i wasn't really motivated, i really wanna try to grind hard next season and get better

https://play.esea.net/users/1099370
http://steamcommunity.com/id/ether_

posted about 7 years ago
#716 ESEA-IM S24 Happenings/Discussion in TF2 General Discussion

ggs 8K, that was the most intense tf2 I've ever played

posted about 7 years ago
1 ⋅⋅ 37 38 39 40 41 42 43 ⋅⋅ 51