glitture's Profile

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SteamID64	76561198121277373
SteamID3	[U:1:161011645]
SteamID32	STEAM_0:1:80505822
Country	Morocco
Signed Up	July 24, 2015
Last Posted	July 18, 2020 at 4:43 PM
Posts	882 (0.3 per day)

Account Details

SteamID64

76561198121277373

SteamID3

[U:1:161011645]

SteamID32

STEAM_0:1:80505822

Country

Morocco

Signed Up

July 24, 2015

Last Posted

July 18, 2020 at 4:43 PM

Posts

882 (0.3 per day)

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In-game Sensitivity	2
Windows Sensitivity	5/11
Raw Input	1
DPI	800
Resolution
Refresh Rate	60 Hz

Game Settings

In-game Sensitivity

Windows Sensitivity

5/11

Raw Input

DPI

800

Resolution

Refresh Rate

60 Hz

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Mouse
Keyboard
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Headphones
Monitor

Hardware Peripherals

Mouse

Keyboard

Mousepad

Headphones

Monitor

#90 Official Full Tilt i58 Fundraiser in TF2 General Discussion

can someone do lan vlogs i wanna see how hard b4nny will try to ignore thalash

posted about 8 years ago

#17 forums where i can for ask help with math? in Off Topic

i love u

posted about 8 years ago

#14 forums where i can for ask help with math? in Off Topic

rocketslay#2:
If n is prime, then for all numbers 1, 2, 3, ..., n-1, gcd(x,n) = 1, which follows from the definition of a prime number, so A(n) = n-1.
If n isn't prime, then for some number in 2, 3, ..., n-1, that number divides n, so A(n) < n-1.
#3:
If p is not a divisor of m, then p and m share no common factors, i.e. gcd(p, m) = 1. Therefore gcd(p^k, m) = 1.
If p divides m, clearly gcd(m, p^k) > 1.
#4: We want the number of integers between 1 and p^n that have no common factors with p^n. From #3, we know that unless x is a multiple of p, gcd(x, p^n) = 1. So we calculate the number of multiples of p between 1 and p^n, which is just p^(n-1). And the total number of integers between 1 and p^n is p^n, so the answer is A(p^n) = p^n - p^(n-1).

thanks a ton man :) i can give you some hats if you want to (sry its the only thing i have)

posted about 8 years ago

#11 forums where i can for ask help with math? in Off Topic

zxppost it here?

∀n∈ℕ: A(n)=card { k∈[1;n]/ gcd(k;n)=1} **(k is also an integer)**
1) calculate A(1) and A(13) and A(20)
2) n∈ℕ-{0;1}, prove that A(n)=n-1 only if n is a prime number
3) p is a prime number, and (k;m)∈ℕ*², prove that gcd(m;p^k)≠1 only if p/m **(p is a divisor of m)**
4) conclude that A(p^n)=(p^n)-(p^(n-1)) for all n ∈ ℕ*

formatting is hard sorry for the mess :(
but srsly tho if anyone can solve question 2, 3 and 4 i will be forever grateful

posted about 8 years ago

#1 forums where i can for ask help with math? in Off Topic

my friend said he'd pay me money if i manage to correctly answer an exercise, i've been trying to do it for the past 4 hours but i think i'm not gonna be able to
is there some sort of forums where you can ask people to help you with something like this?
thanks :)

posted about 8 years ago

#2 Florida LAN Pictures in LAN Discussion

http://imageshack.com/i/plmu6byAj

id on that taylor swift shirt? looks dope

posted about 8 years ago

#10 spotify lowering fps in Off Topic

why not?

posted about 8 years ago

#7 spotify lowering fps in Off Topic

wrusince theres a spotify related thread I have a question: spotify isnt available in my country and I thought about asking somebody from where its available to sign up using my email and then download the app with another apple id (which I already used to download pokemon go), so the question is, will I be able to use it that way? kinda derailing but maybe there are people who know something about that

just get hola for chrome and use spotify web, it works perfectly for me

posted about 8 years ago

#5 4 years looking for a song in Music, Movies, TV

post here https://www.reddit.com/r/tipofmytongue

posted about 8 years ago

#1 isn't this bdonski in The Dumpster

http://i.imgur.com/VXl7bxA.png

lmao

posted about 8 years ago

#3 Help On Starting A Stream in Off Topic

what throne said, but you shouldn't neglect your studies for it, school is important

posted about 8 years ago