http://www.wolframalpha.com/input/?i=limit+as+x+goes+to+infinity+of+%5Bx%5E10%29+%2B+3x%5E9%5D%5E%281%2F10%29+-+x

I'm pretty sure the way to get the solution is to take the taylor series expansion, and then plug in infinity for x, which removes all the terms except 3/10.

It's been far too long since I've taken calc 2 to remember exactly.

Let
A = (x^10 + 3x^9)^(1/10) - x

Turn this into a fraction
A = [x(x^10 + 3x^9)^(1/10) - x^2] / [x]

Limit of this as x goes to infinity is undefined, so use L'Hopital. If you're unfamiliar, it basically says if the limit of some fraction is undefined, take the derivative of the top and bottom instead
lim A = lim [x(x^10 + 3x^9)^(1/10) + (1/10)(x)(x^10 + 3x^9)^(-9/10)(10x^9 + 27x^8) - 2x] / [1]

Just rearranging some stuff
lim A = lim x(x^10 + 3x^9)^(1/10) - x + (1/10)(x)(x^10 + 3x^9)^(-9/10)(10x^9 + 27x^8) - x

AHA
lim A = lim A + (1/10)(x)(x^10 + 3x^9)^(-9/10)(10x^9 + 27x^8) - x

Get rid of those As
lim 0 = lim (1/10)(x)(x^10 + 3x^9)^(-9/10)(10x^9 + 27x^8) - x
lim x = lim (1/10)(x)(x^10 + 3x^9)^(-9/10)(10x^9 + 27x^8)
lim 10 = lim (x^10 + 3x^9)^(-9/10)(10x^9 + 27x^8)

Uhhh let's multiply by (x^10 + 3x^9)/(10x^9 + 27x^8) on both sides and see what happens
lim 10(x^10 + 3x^9)/(10x^9 + 27x^8) = lim (x^10 + 3x^9)^(1/10)

Subtract x
lim 10(x^10 + 3x^9)/(10x^9 + 27x^8) - x = lim (x^10 + 3x^9)^(1/10) - x

WUT
lim 10(x^10 + 3x^9)/(10x^9 + 27x^8) - x = lim A
lim 10x^10/(10x^9 + 27x^8) + 3x^9/(10x^9 + 27x^8) - x = lim A

Pretty easy to simplify
lim x + 3/10 - x = lim A
lim A = lim 3/10

I was doing the derivatives for l'hopitals when you posted this

ugh

#algebra2

u guys r so smart ^^

fuck taylor expansions

TAKE THE SQUARE RoOT OF MY JORTS AND sUFFOCATE ME W ITh IT

agreed

finished calc 1 and never looked back

i barely remember anything from calculus

i had to take calc 1,2, and 3

I'm already 3 math courses past that and can't remember that shit at all D:

should I be scared for engineering

only if you don't like math.

the answer is 2

Definitely not, Engineering is FUN!! Math is fucking boring though. I love my engineering classes that use math in them(read: all), but classes that are purely math are very boring. Only things three things to take out of calc that I use for engineering is diff. eq., derivatives (sometimes), and integrals (sometimes). I've only mainly used diff eq though

#16

Really? That's really surprising that you don't use math that often, how far into your engineering program are you? And what discipline of engineering are you in, civil?

I personally am not a physics major, but I tutor/help them with some of their math, and quantum mechanics, optics, Pretty much any astronomy involving flight patterns, etc etc all use quite a bit of calc. Or atleast their work, and text books within said fields utilize calculus.

Yea I didn't mention that I've only taken like 4 or 5 engineering classes :D, also I'm EE(electrical).

http://www.youtube.com/watch?v=PWoBRVO9PDE

I actually thought you were trolling at first. Good luck dude, where I come from we make fun of EE students because of their tears of desperation. And by that I mean, fucking 23 year olds actually crying. Crying.

FAILED CALC 1 TWICE AND JUST GOT 60% ON THE MIDTERM ON MY 3RD TRY #YOLO #ARTSMAJOR

at the very least stay out of electrical engineering if you hate math. Dat complex calculus

Depends what kind of engineering you want to got into, some degrees have more math courses than others (like electrical engineering mentioned above), but the one I'm in (2nd year computer engineering student) isn't too bad. I only failed calc 2 because I quite literally did nothing.

Also fuck taylor expansions

EDIT: The weird thing is that it doesn't seem like I'm really using all the math that I'm learning at school for what computer/programming classes I have now. Maybe it's only for later.

nah, it'll never apply except for some hardware stuff